Question

if 3.51 g of cuno3 is dissolved in water to make a 0.300 m solution, what is the volume of the solution in milliliters? volume:

Answer 1

To determine the volume of a 0.300 M Cu(NO3)2 solution that results from dissolving 3.51 g of the compound, first calculate the molar mass of Cu(NO3)2, then find the moles of Cu(NO3)2, and finally use the molarity formula to find the volume of solution in liters and convert it to milliliters.

Step-by-step explanation:

To calculate the volume of solution in which 3.51 g of Cu(NO3)2 is dissolved to make a 0.300 M solution, we first need to know the molar mass of Cu(NO3)2. The molar mass can be calculated by adding the atomic masses of all atoms in the compound. Once we have the molar mass, we can use the molarity formula, which is:

Molarity (M) = moles of solute / liters of solution

From this formula, we rearrange to solve for the volume of solution:

Volume of solution (L) = moles of solute / Molarity (M)

To find the moles of Cu(NO3)2, we divide the mass of the compound by its molar mass:

Moles of Cu(NO3)2 = mass (g) / molar mass (g/mol)

Once we find the moles of Cu(NO3)2, we plug it into the rearranged molarity equation to find the volume in liters, and then convert that volume to milliliters by multiplying by 1000 mL/L.

Answer 2

Answer: The volume of the solution is 93.3mL.

Step-by-step explanation:

1) MASS/MOLAR MASS

3.51 g/125.5 g/mol = 0.028 mol

2) # of moles/ volume

0.028/0.300 = 0.0933 = 93.3 mL