Question

E. O 14.182 J11. Under the influence of conservative forces only,an object of mass 9 kg is displaced frompoint A to point B. Its potential energy and speed at point Arespectively are 150 J and 24 m/s. Its potential energy at point B is -100 J.Calculate its speed at point B. (1 point)A. 44.248 m/sB.25.131 m/s4C.33.536 m/sD.7.87 m/sE.40.292 m/sSubmit Query

Answer 1

11)

Answer: B

Step-by-step explanation:

Total energy at point A = kinetic energy + potential energy

We would calculate the kinetic energy at point A by applying the formula,

Kinetic energy = 1/2mv^2

where

m is the mass

v is the velocity

From the information given

m = 9

v = 24

Kinetic energy = 1/2 x 9 x 24^2 = 2592 J

Given that potential energy = 150 J,

Total energy at point A = 150 + 2592 = 2742 J

Total energy at point B = total energy at point A = 2724J

Kinetic energy at point B = total energy - potential energy at point B

Given that potential energy at point B = - 100J

Kinetic energy at point B = 2742 - - 100 = 2742 + 100 = 2842

Thus,

2842 = 1/2 x 9 x v^2

v^2 = 2842/4.5 =

v = √(2842/4.5)

v = 25.131 m/s