Question

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of NO can be made when 66 moles of HNO3 are consumed?

Answer 1

they Are 33 because molecule is the add of two or more atom when you add 33+33=66

Answer 2

16.5 moles

Step-by-step explanation:

The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) to form copper (II) nitrate (Cu(NO3)2), nitric oxide (NO), and water (H2O) is:

3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

From the balanced equation, we can see that the mole ratio between HNO3 and NO is 8:2 or 4:1. This means that for every 4 moles of HNO3 that react, 1 mole of NO is produced.

To determine how many moles of NO can be made when 66 moles of HNO3 are consumed, we need to use this mole ratio. We can set up a proportion to solve for the number of moles of NO:

4 moles HNO3 / 1 mole NO = 66 moles HNO3 / x moles NO

Solving for x, we get:

x = (1 mole NO) x (66 moles HNO3 / 4 moles HNO3) = 16.5 moles NO

Therefore, 16.5 moles of NO can be produced when 66 moles of HNO3 are consumed in this reaction.


ALLEN