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Find one value of x xx that is a solution to the equation: ( x^2 + 3 )^2 = 4x^2 + 12

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User King Leon
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To find one value of x that is a solution to the equation (x^2 + 3)^2 = 4x^2 + 12, we can start by expanding the left side of the equation:

(x^2 + 3)^2 = x^4 + 6x^2 + 9

Next, we can simplify the right side of the equation:

x^4 + 6x^2 + 9 = 4x^2 + 12

And finally, we can subtract 4x^2 from both sides to obtain:

x^4 + 2x^2 + 9 = 12

Now, we can subtract 9 from both sides to obtain:

x^4 + 2x^2 = 3

To find a value of x that satisfies this equation, we would need to solve for x using more advanced mathematical techniques such as using a quartic equation solver or using numerical methods such as Newton-Raphson
User Aramis
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