Question

PLEASE HELP 30 POINTS

1.
Determine the kinetic energy of 1500 kg Tow-Mater Truck traveling at 31.0 m/sec.

Show your work.
2.
A base jumper of mass 68.0 kg stands on the edge of a cliff and possesses 16,800 J of potential energy. How high up is this Mountain Dew Man from the base of the cliff?

Show your work

Answer 1

1.

energy : KE = units J

mass: m = 1500m unit

velocity: v = 31v unit m/s

Answer:

KE = 720750 J

2.

energy: KE = 16800 KE unit

mass: m = 68.0m unit

= V

Answer:

v = 22.228757209048 m/s

Answer 2

Answer:1. Using the following formula, we can calculate the kinetic energy of a 1500 kg tow-mapping truck moving at a speed of 31.0 m/s: KE is equal to 0.5 * m * v2, where m is the object's mass and v is its speed.

By entering the data, we obtain the following equation: KE = 0.5 * 1500 kg * (31.0 m/sec) * 2 = 0.5 * 1500 kg * 961 m2/sec * 2 = 723,500 J

Therefore, the 1500 kg Tow-Mater Truck's kinetic energy at 31.0 m/sec is 723,500 J.

2. To determine the height of the cliff, we use the formula: PE = mgh, where m is the mass of the base jumper, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.

Given that the base jumper has 16,800 J of potential energy, we can rearrange the formula to find h: h = PE / (m * g) = 16,800 J / (68.0 kg * 9.8 m/s^2) = 20.6 m

So, the base jumper is 20.6 meters above the base of the cliff.

Step-by-step explanation: