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Square root of 4y-3=d-y, if y=7
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Square root of 4y-3=d-y, if y=7

User Maximo Dominguez
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1 Answer

5 votes

Answer:

d = 12

Explanation:

Apparently you want the value of d that satisfies √(4y-3) = d-y when y=7.

Solution

Substituting y=7, the equation becomes ...

√(4·7 -3) = d -7 . . . . substitute y=7

√25 = d -7 . . . . . . simplify root

5 +7 = d . . . . . . . add 7

d = 12

Square root of 4y-3=d-y, if y=7-example-1
User Steve Banton
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