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Solve the system of equations using either substitution or elimination

-3x+5y=20
4x+8y=32

2 Answers

3 votes

(i) x–3y–3=0

3x–9y–2=0

Comparing these with pair of equations of the form a

1

x+b

1

y+c

1

=0

and a

2

x+b

2

y+c

2

=0,

a

2

a

1

=

3

1

,

b

2

b

1

=

−9

−3

=

3

1

,

c

2

c

1

=

2

3

a

2

a

1

=

b

2

b

1

=

c

2

c

1

, the lines have no solution.

(ii) 2x+y=5

3x+2y=8

a

2

a

1

=

3

2

,

b

2

b

1

=

2

1

,

c

2

c

1

=

8

5

a

2

a

1

=

b

2

b

1

, the lines have unique solution.

(iii) 3x−5y=20

6x−10y=40

a

2

a

1

=

6

3

=

2

1

,

b

2

b

1

=

−10

−5

=

2

1

,

c

2

c

1

=

40

20

=

2

1

a

2

a

1

=

b

2

b

1

=

c

2

c

1

, the lines have infinitely many solution.

(iv) x−3y−7=0;3x−3y−15=0

a

2

a

1

=

3

1

,

b

2

b

1

=

−3

−3

=1,

c

2

c

1

=

15

7

a

2

a

1

=

b

2

b

1

, the lines have unique solution.

User Edu
by
7.3k points
3 votes

Answer:

y=4 x=1

Explanation:

(-3x+5y=20)x4

(4x+8y=32)x3

-12x+20y=80

12x+24y=96

-12x+20y=80

+12x+24y=96

---------------------------

44y=176

y=4 x=1

User Shane Duffy
by
8.0k points