Question

A proton moving along the lines of force of a uniform electric

field, the intensity of which is 10 kV/m, increased its speed from 106 m/s
up to 1.1∙ 106 m/s. Find: 1) potential difference between points, 2)
acceleration of a proton, 3) path of a proton during acceleration, 4) work
electric field. The charge of a proton is 1.6 ∙ 10−19 K; the mass of a proton
1.67 ∙ 10−27 kg.

Answer 1

1) The potential difference between points is 100 V. 2) The acceleration of the proton is 10 kV/m. 3) The path of the proton during acceleration is a straight line in the direction of the electric field. 4) The work done by the electric field is 1.6E-19 * 100 = 1.6E-17 J.