Question

The temperature of a 250.0g ball of Iron increases from 19.0C to 32.0C. How much heat did the iron ball gained? Specific heat of Iron: 0.450J/gC

Answer 1

1462.5Joules

Explanations:

The formula for calculating the amount of heat gained is expressed as:

`Q=mc\triangle t`

where:

• m is the mass of the ball of iron = 250.0g

,

• c is the specific heat capacity = 0.450J/gC

,

• △t is the change in temperature = 32 - 19 = 13oC

Substitute the given parameters

`\begin{gathered} Q=250g*(0.450J)/(g^0C)*13^0C \\ Q=1462.5Joules \end{gathered}`

Therefore the amount of heat the ball gained is 1462.5Joules