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A quantity of steam (250 g) at 128°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?

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the heat removed from the steam is 128000 J.

When steam is condensed into water, its temperature decreases from 128°C to 0°C. During this process, heat is removed from the steam and transferred to the surrounding environment. This heat transfer can be calculated using the equation:

q = m * c * ΔT

where q is the heat transferred, m is the mass of the steam, c is the specific heat capacity of water, and ΔT is the change in temperature.

For steam, the specific heat capacity is about 4.184 J/g°C. For water, the specific heat capacity is about 4.184 J/g°C as well.

Plugging in the values, we have:

q = 250 g * 4.184 J/g°C * (128°C - 0°C)

q = 250 * 4.184 * 128

q = 128000 J

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