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4x-(6x+1)≤ 8x + 2(x-3)

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Answer:

-1/6

Explanation:

To solve the inequality 4x-(6x+1)≤ 8x + 2(x-3), we can simplify both sides of the inequality and isolate x on one side:

4x - (6x + 1) ≤ 8x + 2(x-3)

4x - 6x - 1 ≤ 8x + 2x - 6

-2x - 1 ≤ 10x - 6

Subtract 10x from both sides:

-12x - 1 ≤ -6

Add 12x to both sides:

-1 ≤ 6x

Divide both sides by 6:

-1/6 ≤ x

The solution to the inequality is x ≥ -1/6. This means that x is greater than or equal to -1/6, so any value of x that is greater than or equal to -1/6 will satisfy the inequality.

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