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Calculate the freezing point of 0.300 molal aqueous solution of magnesium chloride,

(MgCl₂). Assume that the MgCl₂ has ionized completely and the Kf= 1.853 °C / molal

2 Answers

1 vote

Answer: answer of the question is given below

Step-by-step explanation:

Calculate the freezing point of 0.300 molal aqueous solution of magnesium chloride-example-1
User Mono
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3 votes

Answer:

0.556 °C.

Step-by-step explanation:

The freezing point depression of a solution can be calculated using the equation:

ΔTf = Kf x molality

Where ΔTf is the change in freezing point, Kf is the molal freezing point depression constant, and molality is the concentration of solute in mol/kg.

For magnesium chloride, Kf = 1.853 °C/molal. The molality of the solution can be calculated as follows:

molality = moles of solute / mass of solvent (in kilograms)

= 0.300 mol / (0.300 mol x 1000 g/mol) = 0.300 g/1000 g = 0.0003 kg/kg = 0.300 mol/kg

Now, substituting the values into the equation:

ΔTf = Kf x molality

= 1.853 °C/molal x 0.300 mol/kg

= 0.556 °C

So the freezing point of the 0.300 molal aqueous solution of magnesium chloride will be lower than the freezing point of pure water by 0.556 °C.



ALLEN

User Shibaprasad
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