Answer:
To calculate the forces acting on the block, we can use the following steps:
Draw a force diagram showing all the forces acting on the block. The forces acting on the block are:
Weight (W), which acts vertically downward with a magnitude of W = m * g, where m is the mass of the block and g is the acceleration due to gravity (g = 9.8 m/s^2)
Normal force (N), which acts vertically upward to balance the weight and prevent the block from sinking into the surface of the plane
Frictional force (f), which acts parallel to the plane in the direction opposite to the motion of the block
Applied force (F), which acts parallel to the plane in the direction of the motion of the block
Calculate the component of the weight that is parallel to the inclined plane. The weight can be resolved into two components, one perpendicular to the plane (Wcosθ) and one parallel to the plane (Wsinθ).
Wcosθ = W * cos(25°) = (6 kg) * (9.8 m/s^2) * cos(25°) = 50.18 N
Wsinθ = W * sin(25°) = (6 kg) * (9.8 m/s^2) * sin(25°) = 59.16 N
Calculate the magnitude of the normal force. The normal force is equal to the component of the weight that is perpendicular to the plane.
N = Wcosθ = 50.18 N
Calculate the magnitude of the frictional force. The frictional force is equal to the magnitude of the applied force minus the component of the weight that is parallel to the plane.
f = |F - Wsinθ| = |37173 N - 59.16 N| = 37113.84 N
Note that the frictional force opposes the motion of the block and its magnitude is limited by the maximum static friction force, which is given by fmax = μN, where μ is the coefficient of friction between the block and the plane. In this case, since the block is moving at a constant velocity, the frictional force must be equal to the applied force, so that f = 37173 N and μ can be calculated as μ = f / N = 37173 N / 50.18 N = 739.
Step-by-step explanation: