Question

Consider the line 9x-8y=-9.

Find the equation of the line that is parallel to this line and passes through the point (−3, 4).
Find the equation of the line that is perpendicular to this line and passes through the point (-3, 4).
Equation of parallel line:
Equation of perpendicular line:
1
=
X
0=0
5

Answer 1

The equation of the line parallel to the given line 9x-8y=-9 and passing through the point (-3, 4) is 9x-8y=7. The equation of the line perpendicular to the given line and passing through the point (-3, 4) is 8x+9y=-33.