Answer:
(c) 4.4g
Step-by-step explanation:
Given:
mass of calcium carbonate (mCaCO3) = 10g
MrCaCO3 = 100
To find: mCO2
Solution:
CaCO3 + 2HCl → CaCl 2 + H2O + CO2
Now,
MrCaCO3 = 40 + 12 + 16.3 = 100
Therefore,
Number of moles (n) = m/Mr
nCaCO3 = 10/100 = 0.1
The amount of moles is proportional to the coefficient of the reaction. Since both calcium carbonate (CaCO3) and carbon dioxide (CO2) have the same coefficient.
nCO2 = 0.1
MrCO2 = 12 + 16.2 = 44
mCO2 = 0.1 × 44 = 4.4g