Answer:
24.2 cm3 of CO2 will be produced.
Step-by-step explanation:
This equation is balanced, meaning that the number of atoms of each element is the same on both sides of the equation. To determine the volume of the product, CO2, formed from a reaction of 50 cm3 of CO and 30 cm3 of O2, we need to consider the stoichiometry of the reaction, which states the relative proportions of the reactants and products.
The balanced equation is:
2CO + O2 -> 2CO2
This means that 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2. To determine the volume of the CO2 produced, we need to know the number of moles of CO and O2.
Assuming that the volumes of CO and O2 are measured at the same temperature and pressure, we can use the ideal gas law to convert the volumes to moles:
n = PV/RT
where n is the number of moles, P is the pressure, V is the volume, R is the gas constant, and T is the temperature.
Let's use 50 cm3 of CO as an example:
n = (1 atm)(50 cm3) / (0.08206 L * atm / mol * K)(298 K) = 0.11 moles of CO
Similarly, we can calculate the number of moles of O2:
n = (1 atm)(30 cm3) / (0.08206 L * atm / mol * K)(298 K) = 0.06 moles of O2
Since the balanced equation states that 2 moles of CO react with 1 mole of O2, we can use the smaller number of moles, 0.06 moles of O2, to calculate the number of moles of CO2 produced:
0.06 moles of O2 * 2 moles of CO2 / 1 mole of O2 = 0.12 moles of CO2
Finally, we can convert the number of moles of CO2 to a volume using the ideal gas law:
V = nRT/P = (0.12 moles)(0.08206 L * atm / mol * K)(298 K) / (1 atm) = 24.2 cm3
So, if 50 cm3 of CO and 30 cm3 of O2 react, 24.2 cm3 of CO2 will be produced.