Answer:
see explanation
Explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
(a)
given m = 3 , then
y = 3x + c ← is the partial equation
to find c substitute (1, 4 ) into the partial equation
4 = 3(1) + c = 3 + c ( subtract 3 from both sides )
1 = c
y = 3x + 1 ← equation of line
(b)
given m = 4 , then
y = 4x + c ← is the partial equation
to find c substitute (- 1, - 2 ) into the partial equation
- 2 = 4(- 1) + c = - 4 + c ( add 4 to both sides )
2 = c
y = 4x + 2 ← equation of line
(c)
given m = - 1 , then
y = - x + c ← is the partial equation
to find c substitute (3, 0 ) into the partial equation
0 = - 3 + c ( add 3 to both sides )
3 = c
y = - x + 3 ← equation of line
(d)
given m = - 5 , then
y = - 5x + c ← is the partial equation
to find c substitute (0, 0 ) into the partial equation
0 = - 5(0) + c = 0 + c ⇒ c = 0
y = - 5x ← equation of line