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Find the area of an isosceles triangle whose one side is 10 cm greater than each of its equal sides and perimeter is 100 cm.

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Answer:

the area of the isosceles triangle is approximately 104.49 cm^2.

Explanation:

The perimeter of the triangle is 100 cm, so we can write an equation using the lengths of the sides:

x + x + (x + 10) = 100

3x + 10 = 100

3x = 90

x = 30

So the equal sides of the triangle have length 30 cm and the side that is 10 cm greater has length 40 cm.

To find the area of the triangle, we can use the formula for the area of an equilateral triangle:

Area = (sqrt(3) / 4) * (side length)^2

Area = (sqrt(3) / 4) * 30^2

Area = (sqrt(3) / 4) * 900

Area = (sqrt(3) / 4) * 30 * 30

Area = (sqrt(3) / 4) * 900

Area = (30 * sqrt(3)) / 2

Area = 45 sqrt(3)

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