Answer:
Step-by-step explanation:
The most probable speed of a molecule in a gas can be calculated using the Maxwell-Boltzmann distribution. The formula for the most probable speed is given by:
v_mp = (2kT/m)^(1/2)
Where v_mp is the most probable speed, k is the Boltzmann constant (1.38 x 10^-23 J/K), T is the temperature (270 K), and m is the mass of the ozone molecule (48 g/mol, or 48 x 10^-3 kg).
v_mp = (2 * 1.38 x 10^-23 * 270 / 48 x 10^-3)^(1/2)
v_mp = (2.68 x 10^-21 * 270 / 48 x 10^-3)^(1/2)
v_mp = (6.71 x 10^-20 / 48 x 10^-3)^(1/2)
v_mp = (6.71 x 10^-17)^(1/2)
v_mp = 2.59 x 10^-8 m/s
So the most probable speed of an ozone molecule in the stratosphere, where the temperature is 270 K, is approximately 2.59 x 10^-8 m/s.