Question

What are the coordinates of Square ABCD with vertices A(-5,0), B(3,0), C(-5,-8) and D (3,-8) after it has been translated (x,y) -> (x-4, y+6)? A B' D' C' Your answer

Answer 1

We need to know the translation rule:

(x, y ) ---> (x - 4, y + 6).

Then, for each point of the square, we need to apply the previous rule. Then, we have:

For vertice A(-5, 0):

(-5, 0) ---> (-5 - 4, 0 + 6) = (-9, 6)

For vertice B(3, 0):

(3, 0) ---> (3 - 4, 0 + 6) = ( -1, 6)

For vertice C(-5, -8):

(-5, -8) ---> (-5 - 4, -8 + 6) = (-9, -2)

For vertice D(3, -8):

(3, -8) ---> (3 - 4, -8 + 6) = (-1, -2).

Therefore, the coordinates of the image A'B'C'D' is:

(-9, 6), ( -1, 6), (-9, -2), (-1, -2).

To each case, we translate the points four units to the left ( -4) on the x-axis, and 6 units up on the y-axis.