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A 6 kg block is moving at 8 m/s. What will be the block's velocity after a 24 Ns impulse

was applied to it?

User AHunter
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1 Answer

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The change in velocity of an object is given by the equation Δv = F * t / m, where Δv is the change in velocity, F is the force applied, t is the time over which the force is applied, and m is the mass of the object.

In this case, the impulse applied to the block is 24 Ns, and the mass of the block is 6 kg. The time over which the force is applied can be calculated as t = Impulse / Force = 24 Ns / 24 N = 1 s.

Using these values, we can calculate the change in velocity of the block as follows:

Δv = F * t / m = 24 N * 1 s / 6 kg = 4 m/s

So, the velocity of the block after the impulse is applied would be v = v0 + Δv = 8 m/s + 4 m/s = 12 m/s.

User Zdtorok
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