The quadratic equation y2 + 7y - 2 = 0 can be solved using the quadratic formula, which states that the solutions for x in the equation ax^2 + bx + c = 0 are given by:
x = (-b ± √(b^2 - 4ac)) / 2a
We can apply the quadratic formula to this equation by letting a = 1, b = 7, and c = -2:
y = (-7 ± √(7^2 - 4 * 1 * -2)) / 2 * 1
y = (-7 ± √(49 + 8)) / 2
y = (-7 ± √57) / 2
So the solutions to the equation y2 + 7y - 2 = 0 are:
y = (-7 + √57) / 2
y = (-7 - √57) / 2
The solutions to the equation are y = (-7 + √57) / 2 and y = (-7 - √57) / 2.