Question

Sickle cell anemia is a codominant disorder , where AA stands for normal red blood cells and SS stands for sickle- shaped red blood cells . Heterozygous individuals have a phenotype showing both sickle - celled and normal - shaped red blood cells . Cross two people who are both heterozygous for this trait . Show genotypic and phenotypic percentages of the generation

Answer 1

Answer: The genotypic percentages for the offspring of two heterozygous individuals for the sickle cell anemia trait would be 25% AA (normal red blood cells), 50% AS (mixed phenotype), and 25% SS (sickle-shaped red blood cells). The phenotypic percentages for the offspring would be 75% mixed phenotype (AS) and 25% sickle-shaped red blood cells (SS).

Step-by-step explanation:

Sickle cell anemia is a codominant disorder, which means that both alleles of a heterozygous individual are expressed equally. In this case, the heterozygous phenotype shows a mixture of normal red blood cells (AA) and sickle-shaped red blood cells (SS).

When two heterozygous individuals (AS) are crossed, the possible offspring genotypes are:

AA (normal red blood cells) = 1/4 of the offspring

AS (mixed phenotype) = 1/2 of the offspring

SS (sickle-shaped red blood cells) = 1/4 of the offspring

So, the genotypic percentages for the offspring would be 25% AA (normal red blood cells), 50% AS (mixed phenotype), and 25% SS (sickle-shaped red blood cells).

The phenotypic percentages for the offspring would be 75% mixed phenotype (AS) and 25% sickle-shaped red blood cells (SS), as both alleles are expressed equally in the AS phenotype.

It's important to note that sickle cell anemia is a serious disorder that can cause a wide range of health problems, including anemia, pain, and increased risk of infections. Individuals with sickle cell anemia typically require medical treatment and support to manage their condition.