Final answer:
To find how far the shell lands past the edge of the cliff, you need to use the equations of projectile motion. The vertical displacement is 0 because the ground is at the same level as the cliff. By calculating the time it takes for the shell to reach the ground and using the equation for horizontal range, you can find the answer.
Step-by-step explanation:
To find how far the shell lands past the edge of the cliff, we can use the equations of projectile motion.
First, we need to calculate the time it takes for the shell to reach the ground. Since the ground is at the same level as the cliff, the vertical displacement is 0. We can use the formula:
Δy = v_iy * t + (1/2) * a_y * t^2
Since the initial vertical velocity, v_iy, is 0 (since there is no vertical component to the initial velocity), the equation simplifies to:
0 = (1/2) * a_y * t^2
Solving for t, we find that t = 0 or t = √(2 * Δy / a_y). Since we are interested in the time it takes for the shell to hit the ground, we take the positive root:
t = √(2 * Δy / a_y)
Substituting the values, Δy = -25.0 m (the negative sign indicates that the displacement is in the downward direction) and a_y = -9.8 m/s^2 (acceleration due to gravity), we can calculate the time t.
Once we have the time, we can calculate the horizontal range using the formula:
R = v_ix * t
where v_ix is the initial horizontal velocity.
However, since we are not given the angle of projection or the initial horizontal velocity, we cannot calculate the exact range. We need more information to solve the problem.