Question

This circle is centered at the point (2, 6), and the length of its radius is 4. Whatis the equation of the circle?-101010(2, 6),10A. (x-6)2 + (y-2)² = 16B. (x + 2)2 + (y+ 6)² = 4C. (²-2) +(²-6) = 4²D. (x-2)2+(-6)² = 16

Answer 1

D. (x - 2)² + (y - 6)² = 16

Step-by-step explanation

The equation of a circle in standard form is,

`(x-h)^2+(y-k)^2=r^2`

Where r is the radius and (h, k) is the center of the circle.

In this case, we have a circle with center at (2, 6) and radius of 4, so the equation is,

`\begin{gathered} (x-2)^2+(y-6)^2=4^2 \\ \\ (x-2)^2+(y-6)^2=16 \end{gathered}`

Hence, the equation of the circle is (x - 2)² + (y - 6)² = 16.