Question

How do you solve quadratic using square roots?ex: 3/4(x+1)²=10

Answer 1

Explanation:

First, we multiply both sides by 4/3 to get

`(4)/(3)\cdot(3)/(4)(x+1)^2=10\cdot(4)/(3)`
`(x+1)^2=(40)/(3)`

Taking the square root of both sides gives

`\sqrt[]{(x+1)^2}=\sqrt[]{(40)/(3)}`
`x+1=\sqrt[]{(40)/(3)}`

Finally, subtracting 1 from both sides gives

`\boxed{x=\sqrt[]{(40)/(3)}-1}`

which is our answer!