Answer:
55 L of water
Explanation:
11-L of 60% acid contains 0.6 × 11 L = 6.6 L acid
Let x = amount of pure water.
Let y = total amount produced of 90% water solution.
A 90% water solution is a 10% acid solution.
Amounts of solutions:
x + 11 = y
Amounts of acid:
6.6 = 0.1y
y = 66
x + 11 = 66
x = 55
Answer: 55 L of water
55 L water has 0 acid.
11 L 60% acid solution has 6.6 L acid.
66 L of 10% acid solution has 6.6 L acid