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PLEASEE ANSWER ASAPP!!

The system of linear equations −3x + 2y = −6 and y equals negative one half times x plus 4 is graphed on a coordinate plane. Approximate the solution to the system.

PLEASEE ANSWER ASAPP!! The system of linear equations −3x + 2y = −6 and y equals negative-example-1

1 Answer

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Answer: the solution to the system of equations is approximately (3.5, 2.25)

Explanation:

The first equation can be rewritten in the form y = mx + b, where m is the slope and b is the y-intercept, by solving for y:

-3x + 2y = -6

2y = 3x + 6

y = (3/2)x + 3

The second equation already has the form y = mx + b:

y = -1/2 x + 4

Now that both equations are in the form y = mx + b, we can graph them on a coordinate plane and find the point at which they intersect, which is the solution to the system. The x and y coordinates of the intersection point are the values that satisfy both equations simultaneously.

The x and y values of the intersection point can be found either by solving for x and y or by using the method of substitution.

By using substitution, we can substitute the value of y from the second equation into the first equation to solve for x:

-3x + 2(-1/2 x + 4) = -6

-3x + (-x + 8) = -6

-4x + 8 = -6

-4x = -14

x = 3.5

Now that we have found x, we can substitute it into either equation to find y:

y = -1/2 x + 4

y = -1/2 * 3.5 + 4

y = 2.25

So, the solution to the system of equations is approximately (3.5, 2.25).

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