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36 votes
I got a question for a school assignment if you guys could help me out k would appreciate it a lot please and thank you.

I got a question for a school assignment if you guys could help me out k would appreciate-example-1
User Menghan
by
3.1k points

1 Answer

23 votes
23 votes

Solution

Step 1

The surface area of the square pyramid

= Sum of the area of the four triangular faces and the area of the square base.

Step 2


\begin{gathered} \text{Area of the triangular face = }\frac{Base\text{ }*\text{ Height}}{2} \\ Base\text{ = 0.8 foot} \\ Height\text{ = 6 feet} \\ Area\text{ of the triangular face = }\frac{0.8\text{ }*\text{ 6}}{2}\text{ = 2.4 ft}^2 \\ Area\text{ of the four triangular faces = 4 }*\text{ 2.4 = 9.6 ft}^2 \\ Area\text{ of the square base = L}^2\text{ = 0.8}^2\text{ = 0.64} \end{gathered}

Step 3


Surface\text{ area of the square pyramid = 9.6 + 0.64 = 10.24 ft}^2

Final answer

10.24 square feet

User Jvi
by
3.0k points