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5) Imani and lea are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of holiday wrapping paper. Imani sold 2 rolls of plain wrapping paper and 11 rolls of holiday wrapping paper for a total of $208. Lea sold 11 rolls of plain wrapping paper and 9 rolls of holiday wrapping paper for a total of $320. What is the cost each of one roll of plain wrapping paper and one roll of holiday wrapping paper?

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Answer: Let's represent the cost of one roll of plain wrapping paper as x, and the cost of one roll of holiday wrapping paper as y. We can write two equations based on the information given:

2x + 11y = 208

11x + 9y = 320

We can use these equations to find the values of x and y. Solving the first equation for y:

y = (208 - 2x) / 11

We can substitute this expression for y into the second equation to eliminate y:

11x + 9((208 - 2x) / 11) = 320

11x + 208 - 18x / 11 = 320

11x - 18x / 11 = 320 - 208

-7x / 11 = 112 / 11

-7x = 112

x = -16

So one roll of plain wrapping paper costs -16 dollars, which is not possible. This means there is no solution for this system of equations, and therefore the problem has no solution.

Explanation:

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