Question

What is the equation of the line that passes through the point (-8, 6) and has a slope

of -1/4?

Answer 1

= 4y + x - 16 = 0.

Explanation:

Point are (-8,6)

where

x1 = -8 and y1 = 6

the equation o the line is given by the formula

`= (y - y1)/(x - x1) = m`

where (m) is the gradient

the gradient (m) = -1/4

therefore the equation of the line

`(y - y1)/(x - x1) = m \\ = (y - 6)/(x - ( - 8)) = ( - 1)/(4) \\ = (y - 6)/(x + 8) = ( - 1)/(4) \\ = 4(y - 6) = - 1(x + 8) \\ = 4y - 24 = - x - 8 \\ = 4y = - x - 8 + 24 \\ = 4y = - x + 16 \\ = 4y + x - 16 = 0.`

therefore the equation of the line is = 4y + x - 16 = 0.

note// y and x where not given any value.