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The percentage of oxygen in sodiumtrioxocarbonate(vi) dehydrated is​

User Sanchitos
by
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1 Answer

5 votes

Answer:45.27 Explanation: To find the mass percent of oxygen we begin by finding the mass of the molecule

N

a

2

C

O

3

N

a

=

2

22.99

=

45.98

C

=

1

12.01

=

12.01

O

=

3

15.99

=

47.97

N

a

2

C

O

3

=

105.96

Now divide the mass of Oxygen by the total mass of the molecule.

47.97

105.96

=

.4527

Multiply 100 to convert the decimal to a percent.

.4527

100

=

45.27

%

User Jamesconant
by
6.9k points