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A train leaves San Diego at 4:00 PM. A second train leaves the same city in the same direction at 6:00 PM. The second train travels 42mph faster than the first. If the second train overtakes the first at 8:00 PM, what is the speed of each of the two trains?

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This problem can be solved using algebra. Let's call the speed of the first train "x". Then, the speed of the second train would be x + 42.

We also know that the second train overtakes the first after 4 hours, so we can write an equation for the distance each train travels:

x * 4 = (x + 42) * 2

Expanding and solving for x, we can find that the speed of the first train is 50 mph and the speed of the second train is 92 mph.
User Mark Dominus
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