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How many ways can 3 of 10 students come first, second and third place is a spelling contest, if there are no ties?

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Answer:

Explanation:

The number of ways to choose 3 students out of 10 to come in first, second, and third place in a spelling contest, with no ties, is calculated using the combination formula. The combination formula is:

C(n, r) = n! / (r! (n-r)!)

Where n is the total number of items, and r is the number of items to choose. In this case, n = 10 and r = 3.

So, the number of ways to choose 3 students out of 10 is:

C(10, 3) = 10! / (3! (10-3)!) = 10! / (3! 7!) = 10 x 9 x 8 / (3 x 2 x 1) = 120.

Therefore, there are 120 different ways to choose 3 students out of 10 to come in first, second, and third place in a spelling contest, with no ties.

User Paulo Matos
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