Final answer:
The student does 200 J of work on the cart. The total work done on the cart is 220 J. The final speed of the cart cannot be determined without knowing its mass.
Step-by-step explanation:
(A) To draw a Free Body Diagram (FBD), we need to identify and label all the forces acting on the cart. In this case, we have the applied force (Fapp) of 20N at an angle of 25 degrees above the horizontal, the gravitational force (Fg) acting vertically downwards, and the frictional force (Ff) opposing motion.
(B) The work done by the student can be found using the formula: Work = Force x Distance. In this case, the applied force is 20N, and the distance moved is 10m. So the work done by the student is 20N x 10m = 200 J.
(C) The total work done is the sum of the work done by the student and the work done by friction. Since the work done by friction is equal to the force of friction multiplied by the distance moved, we can calculate it as: Workf = Ff x d = 2N x 10m = 20 J. Therefore, the total work done is 200J + 20J = 220 J.
(D) If the cart starts at rest, we can use the work-energy theorem to determine its final speed. The work done on the cart by the student is equal to the change in its kinetic energy: Workstudent = (1/2)m(vf2 - vi2) where m is the mass. Since the cart starts at rest, its initial velocity is 0. The work done by the student is 200 J, and the mass of the cart is not provided in the question. Therefore, we cannot determine the final speed without knowing the mass of the cart.