Question

AgCl is found to have 78.1% ionic character, and its gas phase dipole moment is 11.5 D. What is the distance between the Ag and Cl atoms in gaseous AgCl?

please explain how as well

Answer 1

The ionic character of a compound can be used to determine the bond polarity, and the gas phase dipole moment can be used to calculate the bond length. The equation for the bond length (r) in terms of the bond polarity (p) and the bond dipole moment (μ) is given by:

r = (μ) / (4πpε_0p)

Where ε_0 is the vacuum permittivity and p is the bond polarity.

For AgCl, the bond polarity can be calculated from the ionic character:

p = 78.1%

So, substituting the values into the equation, we get:

r = (11.5 D) / (4π * 0.781 * 8.854 x 10^-12 C^2/Nm^2) = 2.8 x 10^-10 m

So the distance between the Ag and Cl atoms in gaseous AgCl is approximately 2.8 x 10^-10 meters.

Step-by-step explanation: