Question

I need help with my stoichiometry homework

Answer 1

Below

Step-by-step explanation:

First , note that TWICE as many moles of O2 are required as CH4

so ya need to figure out the number of moles in 12.54 g of CH4

From periodic table find weights of C and H

C = 12.011 H = 1.008 g / mole

so a mole of CH4 is 12.011 + 4 * 1.008 = 16.043 g / mole

now 12. 54 g / 16.043 g/mole = .78 mole of CH4

remember from above, you need twice as many moles of O2

.78 x 2 = 1.56 moles of O2