Question

ABC ~ XYZ, AB = 12, AC = 16, BC= 20, and XZ =

24.
Find the perimeter of AXYZ.

60

72

48

50

Answer 1

Explanation:

Given, the sides of triangle ABC are 12, 16 and 20, which form a right triangle (as 20 is the hypotenuse).

Let us assume that the sides of triangle XYZ are x, y and 24 (XZ=24).

Since ABC ~ XYZ, we can use ratios of corresponding sides to find the lengths of the sides of triangle XYZ:

x/12 = y/16 = 24/20

Solving for x and y, we get:

x = 9 and y = 12

So, the perimeter of triangle AXYZ = 9 + 12 + 12 + 24 = 57.