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How to solve x(x-2)=48

2 Answers

3 votes

Explanation:

x(x-2)=48

Remove the parentheses

x²-2x=48

Move the constant to the left

x²- 2x - 48=0

Rewrite the expression

x² + 6x - 8x - 48 = 0

Factor the expressions

x(x+6) - 8(x+6) = 0

Separate into possible cases

(x+6) (x-8)=0

x + 6 = 0

x - 8 = 0

x = - 6 or x = 8

User Insanity
by
6.8k points
7 votes

Answer:

x = 8

Explanation:

To solve the equation x(x - 2) = 48 for x, we can first expand the left side:

x^2 - 2x = 48

Next, we'll add 2x to both sides to isolate x^2:

x^2 = 48 + 2x

Then, we'll subtract 2x from both sides:

x^2 - 2x = 48

Now we have a quadratic equation that we can solve for x using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 1, b = -2, and c = 48. Plugging these values into the formula:

x = (-(-2) ± √((-2)^2 - 4(1)(48))) / 2(1)

x = (2 ± √(4 + 192)) / 2

x = (2 ± √196) / 2

x = (2 ± 14) / 2

So the two solutions are x = (2 + 14) / 2 = 8 and x = (2 - 14) / 2 = -6.

Keep in mind that x cannot be negative in this context as it represents a measurement. Therefore, x = 8 is the only solution that has a meaningful value in this context.

User JessieArr
by
7.5k points