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Guys no one answers this :(

A circle is inscribed in quadrilateral ABCD. If AB = 4, BC = 5, and CD = 8,
what is DA?

User Soca
by
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1 Answer

2 votes

Explanation:

the distance from a vertex of the quadrilateral to the touching points on the two sides emanating from the vertex is the same.

and that applies to each of the 4 vertices.

so, AB splits into the distance a (from A to the circle touching point on AB) and b (from the touching point on AB to B).

b = AB - a

in the same way, BC splits into b (B to circle touching point on BC) = AB - a, and c (circle touching point on BC to C).

c = BC - (AB - a) = BC - AB + a

CD splits into c (C to circle touching point on CD) = BC - AB + a, and d (circle touching point on CD to D).

d = CD - (BC - AB + a) = CD - BC + AB - a

DA now splits into d (D to circle touching point on DA) = CD - BC + AB - a, and into ... a (the circle touching point on DA to A).

a = DA - (CD - BC + AB - a) = DA - CD + BC - AB + a

0 = DA - CD + BC - AB

DA = CD - BC + AB = 8 - 5 + 4 = 7

User Wagner Sales
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