Answer:
(x - 2) is not a factor of f(x)
Explanation:
We can use the Remainder Theorem to check if (x - 2) is a factor of f(x) = x^3 - 2x^2 + 2x + 3.
The Remainder Theorem states that if we evaluate a polynomial at a specific value and the result is zero, then that value must be a root of the polynomial and therefore the polynomial can be divided by the corresponding linear factor.
So, if we plug in x = 2 into f(x), we get:
f(2) = 2^3 - 2 * 2^2 + 2 * 2 + 3
= 8 - 8 + 4 + 3
= 7
Since f(2) is not equal to zero, it follows that (x - 2) is not a factor of f(x).
Alternatively, we could use the Factor Theorem, which states that a polynomial is divisible by (x - a) if and only if f(a) = 0. Since f(2) is not equal to zero, (x - 2) is not a factor of f(x).