Question

Let AA be the event that a randomly selected IRSC student is an Associate of Arts student and

P(AA) = 0.41. Let the event PM be the event that a randomly selected IRSC student is on the pre-med
degree track and P(PM) = 0.38. Finally, the probability that a randomly selected IRSC student is an AA degree seeker and on the pre-med degree track is 0.05. Use this information to calculate the following
probability.

Answer 1

P(AA) = 0.41

P(PM) = 0.38

P(AA and PM) = 0.05

As you are finding P(AA or PM), you can apply the formula:

P(A U B) = P(A) + P(B) - P( A ∩ B)

U = Union P( A U B) = P (A or B)

∩ = And

From the formula, you can find out the answer:

P(AA or PM) = P(AA) + P(PM) - P(AA and PM)

= 0.41+0.38-0.05

= 0.74

hope this helps!!!!