Answer:
Explanation:
You want two integers with a product of 36 such that one is 3 less than 5 times the other.
Setup
Let x be "the other" integer. Then one is (5x-3), and the product is ...
x(5x -3) = 36
Solution
5x² -3x = 36 . . . . . . eliminate parentheses
x² -0.6x = 7.2 . . . . . . . divide by 5
x -0.6x +0.09 = 7.29 . . . . . add (0.6/2)² to complete the square
(x -0.3)² = 7.29
x = 0.3 +√7.29 = 0.3 +2.7 = 3
5x -3 = 5·3 -3 = 12
The two integers are 12 and 3.