Answer:
y = (1/2)(x - 2) + ln(2)
Explanation:
The formula for the tangent line to f(x) = ln(x) at x = 2 is given by the equation:
y = f'(2)(x - 2) + f(2)
Where f'(2) is the derivative of f(x) evaluated at x = 2, and f(2) is the value of f(x) evaluated at x = 2.
Given that f(x) = ln(x) and f'(2) = 1/2, we can substitute these values into the equation to get:
y = (1/2)(x - 2) + ln(2)
So the formula for the tangent line to f(x) = ln(x) at x = 2 is:
y = (1/2)(x - 2) + ln(2)