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1. Find the zeros of f(x), and state the multiplicity of each zero. (Order your answers from smallest to largest x.)

a. f(x) = 16x^5 + 56x^4 + 49x^3
x = ________ with multiplicity ________
x= ________ with multiplicity ________

b. f(x) = x(x + 3)^5 (3x - 7)^2
x = ___________ with multiplicity ___________
x = ___________ with multiplicity ___________
x= ___________ with multiplicity ___________

1 Answer

6 votes

Answer:

Part (a)


x=0\; \sf with\;multiplicity\;1


x=-(7)/(4)\; \sf with\;multiplicity\;2

Part (b)


x=0\; \sf with\;multiplicity\;1


x=-3\; \sf with\;multiplicity\;5


x=(7)/(3)\; \sf with\;multiplicity\;2

Explanation:

Part (a)

Given function:


f(x) = 16x^5 + 56x^4 + 49x^3

Factor out the common term x³:


f(x) = x^3(16x^2 + 56x+ 49)

To factor the quadratic factor, rewrite in the form a² + 2ab + b²:


\implies 16x^2+56x+49=(4x)^2+2 \cdot 4x \cdot 7+7^2

Therefore:

  • a = 4x
  • b = 7

Apply the perfect square formula: a² + 2ab + b² = (a + b)²


\implies 16x^2+56x+49=(4x+7)^2

Therefore, the given function in fully factored form is:


f(x)=x^3(4x+7)^2

To find the zeros of the function, set the function to zero:


x^3(4x+7)^2=0

Apply the zero-product property:


\implies x^3=0 \implies x=0


\implies (4x+7)^2=0 \implies x=-(7)/(4)

The multiplicity of a zero refers to the number of times the associated factor appears in the factored form of the equation of a polynomial.

As the factor (4x + 7) appears twice in the factored form of the polynomial, the associated zero has multiplicity 2.

Solution


x=0\; \sf with\;multiplicity\;1


x=-(7)/(4)\; \sf with\;multiplicity\;2

Part (b)

Given function:


f(x) = x(x + 3)^5 (3x - 7)^2

To find the zeros of the function, set the function to zero:


x(x + 3)^5 (3x - 7)^2=0

Apply the zero-product property:


\implies x=0


\implies (x+3)^5=0 \implies x=-3


\implies (3x-7)^2=0 \implies x=(7)/(3)

The multiplicity of a zero refers to the number of times the associated factor appears in the factored form of the equation of a polynomial.

As the factor (x + 3) appears five times in the factored form of the polynomial, the associated zero has multiplicity 5.

As the factor (3x - 7) appears twice in the factored form of the polynomial, the associated zero has multiplicity 2.

Solution


x=0\; \sf with\;multiplicity\;1


x=-3\; \sf with\;multiplicity\;5


x=(7)/(3)\; \sf with\;multiplicity\;2

User Ben Stahl
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