Question

three men owned some money, their shares being 1/2, 1/3, and 1/6. each took some money at random until none was left. the first man then returned 1/2 of what he had taken, the second 1/3 and the third 1/6. when the money now in the pile was divided equally among the men, each possessed what he was entitled to. how much money was in the original store, and how much did each man take?

Answer 1

1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1

Originally, all of the money was taken and then returned.

Then each man took 1/3 of the money (which was equal to that originally present)