Question

Square root of 32, 6, and 2 as a right triangle

Answer 1

Explanation:

1. square root of 32.

`√(32 \\ ) \\ = √(2) * √(16) \\ = √(2) * ( √(4) * √(4) ) \\ = √(2) * √(4) \\ = \sqrt[2]{4} \\ = 2`

2. Square root of 6

`√(6) \\ = √(2) * √(3) \\ = \sqrt[2]{3 \\ } \\ = 1.5`

3. Square root of 2

`√(2) \\ = √(1) * √(1) \\ = \sqrt[1]{1} \\ = 1`