Explanation:
= (c - 4) ( c - 5)
= c ( c- 5 ) -4 (c - 5)
= c² - 5c - 4c + 20
Grouping of like terms since it have already been arranged.
=c² - 9c + 20
since we're finding for the coefficient of c
than we will square both sides or value
given as
![\sqrt{c {}^(2) } - √(9c) + √(20) = 0 \\ c - \sqrt[3]{3c} + \sqrt[2]{10} = 0 \\ c - c + 5 = 0 \\ 0 = 0 - 5 \\ 0 = - 5](https://img.qammunity.org/2024/formulas/mathematics/high-school/si1zcz6gf2wrffdkgbjhmqwg2jnq63jbob.png)
sorry but I tried.