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Carlos is playing a dice game with Elena. Carlos will roll 222 six-sided dice, and if the sum is greater than 777, he will win \$5$5dollar sign, 5. If the sum is 777, they will tie and he will break even. If the sum is less than 777, he will lose \$4$4dollar sign, 4. What is Carlos's expected value of playing this game? Round your answer to the nearest cent.

User Msiyer
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2 Answers

7 votes

Answer:

Explanation:

The expected value of Carlos playing this dice game is

$0.42

User Arjaan Buijk
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7.4k points
6 votes

Answer:

Explanation:

The expected value of one six-sided dice is (1 + 2 + 3 + 4 + 5 + 6)/6 = 3.5.

So, the expected value of the sum of 222 dice is 3.5 * 222 = 777.

This means that the expected value of playing this game is 0, since the expected outcome is to break even.

Thus, Carlos's expected value of playing this game is 0, rounded to the nearest cent.

User Ose
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7.2k points