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5 votes
Write \frac{\sqrt[4]{v^{9}}}{\sqrt[3]{v^{4}}}

3

v
4



4

v
9




as a single radical using the smallest possible root.

User Man Guy
by
8.5k points

1 Answer

5 votes

Answer:


\mbox {\large \boxed{\sqrt[12]{v^(11) }}}\\

Explanation:


\textrm{We are asked to simplify\:$\frac{\sqrt[4]{v^9}}{\sqrt[3]{v^4}}$}

Using the fact that
\sqrt[n]{x} = n^{{1/n}}


\mbox{\large {\sqrt[4]{v^9}} =\left(v^9)^(1/4) = v^(9/4)}\\\\


\mbox{\large {\sqrt[3]{v^4}}} = (v^4)^(1/3) = v^(4/3)}


\mbox{\large $\frac{\sqrt[4]{v^9}}{\sqrt[3]{v^4}}$}
= \mbox{\large (v^(9/4))/(v^(4/3))}

Using the fact that
(x^a)/(x^b) = x^(a-b)


\mbox{\large (v^(9/4))/(v^(4/3)) = v^(9/4 - 4/3)}


(9)/(4) - (4)/(3) = (9 \cdot 3 - 4 \cdot 4)/(12) = (27-16)/(12) = (11)/(12)


\mbox{\large (v^(9/4))/(v^(4/3)) = v^(9/4 - 4/3)= v^(11/12) } = \sqrt[12]{v^(11) }}

Answer

\mbox {\large \boxed{\sqrt[12]{v^(11) }}}\\

User Gokul Thiagarajan
by
8.6k points

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